式の値(11)
２０２６^ｘ=８、１０１３^ｙ=４のとき、３/ｘ－２/ｙの値を求めよ。
x=log[2026]8=log8/log(2026)=3*log(2)/(log(2)+log(1013))
y=log[1013]4=log(4)/log(1013)=2*log(2)/log(1013)
よって
3/x-2/y=(log(2)+log(1013))/log(2)-log(1013)/log(2)=log(2)/log(2)=1
２０２６^ｘ=８、１０１３^ｙ=４のとき、３/ｘ－２/ｙの値を求めよ。
x=log[2026]8=log8/log(2026)=3*log(2)/(log(2)+log(1013))
y=log[1013]4=log(4)/log(1013)=2*log(2)/log(1013)
よって
3/x-2/y=(log(2)+log(1013))/log(2)-log(1013)/log(2)=log(2)/log(2)=1
