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No.1580Dengan kesaktian Indukmu2023幎12æ1æ¥ 22:09
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No.1590ãããã2023幎12æ4æ¥ 06:46
n ïŒ 1 ãšããŸãã
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No.1575Dengan kesaktian Indukmu2023幎11æ29æ¥ 16:58
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No.1581Dengan kesaktian Indukmu2023幎12æ1æ¥ 22:14
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No.1582DD++2023幎12æ2æ¥ 06:38
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No.1583Dengan kesaktian Indukmu2023幎12æ2æ¥ 06:53
nãèªç¶æ°ãšãããšã
2^(2*n) + 2^(2*n+3) + 2^p
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No.1564GAI2023幎11æ27æ¥ 07:00
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No.1565ãããã2023幎11æ27æ¥ 08:21
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ããããããŸãšåãã§ããã
2^(2n)+2^(2n+3)+2^p=a^2ãšãããšã
2^(2n)+8*2^(2n)+2^p=a^2
9*2^(2n)+2^p=a^2
2^p=a^2-9*2^(2n)
2^p=(a+3*2^n)(a-3*2^n)
巊蟺ã¯æ£ã ãããa-3*2^n>0
2^p=(a+3*2^n)(a-3*2^n)
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b+3=2^cãããb=2^c-3
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ã ãšããŠa+3*2^n=8*2^n
ãããã£ãŠã
2^p=(a+3*2^n)(a-3*2^n)
2^p=16*(2^n)* (2^n)=16*2^(2n)=2^4*2^(2n)=2^(2n+4)
ããã«p=2n+4
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No.1566ããããã¯ã¡ã¹ã2023幎11æ27æ¥ 15:04
2^(2*n) + 2^(2*n+3) ã 9*
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No.1567DD++2023幎11æ27æ¥ 17:31
2^(2*n) + 2^(n+3) + 2^p
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ãä»»æã®nãããªãããŠãnã«äŸåããŠããããªãã°nãå¥æ°éå®ã§p=(3n+5)/2ãšãã解ããããŸããã
No.1568ãããã2023幎11æ27æ¥ 18:52
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ïŒ2^p=(a+3*2^n)(a-3*2^n)
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b+3=2^cãããb=2^c-3
b-3=2^dãããb=2^d+3
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b+3=2^cãããb=2^c-3
b-3=2^dãããb=2^d+3
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å³èŸºãå¥æ°ãªã®ã§å·ŠèŸºãæ£ã®å¥æ°ã§ãd-1=0,c-1=2ã®å Žåãããªãã
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aã¯å¶æ°ããa=2m(mã¯æŽæ°)ãšçœ®ããšã2^p=(2m+3*2^n)(2m-3*2^n)
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2^p=(b*2^n+3*2^n)(b*2^n-3*2^n)
âŽ2^(p-2n)=(b+3)(b-3)
ãã£ãŠãb+3=2^cïŒb-3=2^dãšçœ®ãã®ã§ãããïŒp-2n>0ïŒ
No.1569å£ããæ2023幎11æ27æ¥ 19:18
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2^(2*n)+2^(2*n+3)+2^p=m^2 (m;æŽæ°)
ãšãããš
2^p=m^2-2^(2*n)*(1+2^3)
=m^2-(2^n*3)^2
=(m-3*2^n)*(m+3*2^n)
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m-3*2^n=2^sâ
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No.1570GAI2023幎11æ27æ¥ 19:21
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No.1571ããããã¯ã¡ã¹ã2023幎11æ27æ¥ 19:35
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n äŸåã®è©±ããããªããn ãå¥æ°éå®ã§ p = 3n-5 ããããŸãããn = 7 㧠p = 15 ã®ãããªããªãç¹æ®ãªè§£ããããŸãã
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No.1572DD++2023幎11æ27æ¥ 21:33
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No.1573ããããã¯ã¡ã¹ã2023幎11æ28æ¥ 14:09
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